0=-16x^2-15x+28

Solution for 0=-16x^2-15x+28 equation:

0=-16x^2-15x+28

We move all terms to the left:

0-(-16x^2-15x+28)=0

We add all the numbers together, and all the variables

-(-16x^2-15x+28)=0

We get rid of parentheses

16x^2+15x-28=0

a = 16; b = 15; c = -28;
Δ = b2-4ac
Δ = 152-4·16·(-28)
Δ = 2017
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{2017}}{2*16}=\frac{-15-\sqrt{2017}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{2017}}{2*16}=\frac{-15+\sqrt{2017}}{32}
$